Optimal. Leaf size=188 \[ -\frac {2 \left (A b^3-a \left (a^2 D-a b C+b^2 B\right )\right ) \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}\right )}{b^{7/2} \sqrt {b c-a d}}+\frac {2 \sqrt {c+d x} \left (a^2 d^2 D-a b d (C d-c D)-\left (b^2 \left (-B d^2+c^2 (-D)+c C d\right )\right )\right )}{b^3 d^3}+\frac {2 (c+d x)^{3/2} (-a d D-2 b c D+b C d)}{3 b^2 d^3}+\frac {2 D (c+d x)^{5/2}}{5 b d^3} \]
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Rubi [A] time = 0.21, antiderivative size = 188, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 32, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.094, Rules used = {1620, 63, 208} \[ -\frac {2 \left (A b^3-a \left (a^2 D-a b C+b^2 B\right )\right ) \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}\right )}{b^{7/2} \sqrt {b c-a d}}+\frac {2 \sqrt {c+d x} \left (a^2 d^2 D-a b d (C d-c D)+b^2 \left (-\left (-B d^2+c^2 (-D)+c C d\right )\right )\right )}{b^3 d^3}+\frac {2 (c+d x)^{3/2} (-a d D-2 b c D+b C d)}{3 b^2 d^3}+\frac {2 D (c+d x)^{5/2}}{5 b d^3} \]
Antiderivative was successfully verified.
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Rule 63
Rule 208
Rule 1620
Rubi steps
\begin {align*} \int \frac {A+B x+C x^2+D x^3}{(a+b x) \sqrt {c+d x}} \, dx &=\int \left (\frac {a^2 d^2 D-a b d (C d-c D)-b^2 \left (c C d-B d^2-c^2 D\right )}{b^3 d^2 \sqrt {c+d x}}+\frac {A b^3-a \left (b^2 B-a b C+a^2 D\right )}{b^3 (a+b x) \sqrt {c+d x}}+\frac {(b C d-2 b c D-a d D) \sqrt {c+d x}}{b^2 d^2}+\frac {D (c+d x)^{3/2}}{b d^2}\right ) \, dx\\ &=\frac {2 \left (a^2 d^2 D-a b d (C d-c D)-b^2 \left (c C d-B d^2-c^2 D\right )\right ) \sqrt {c+d x}}{b^3 d^3}+\frac {2 (b C d-2 b c D-a d D) (c+d x)^{3/2}}{3 b^2 d^3}+\frac {2 D (c+d x)^{5/2}}{5 b d^3}+\left (A-\frac {a \left (b^2 B-a b C+a^2 D\right )}{b^3}\right ) \int \frac {1}{(a+b x) \sqrt {c+d x}} \, dx\\ &=\frac {2 \left (a^2 d^2 D-a b d (C d-c D)-b^2 \left (c C d-B d^2-c^2 D\right )\right ) \sqrt {c+d x}}{b^3 d^3}+\frac {2 (b C d-2 b c D-a d D) (c+d x)^{3/2}}{3 b^2 d^3}+\frac {2 D (c+d x)^{5/2}}{5 b d^3}+\frac {\left (2 \left (A-\frac {a \left (b^2 B-a b C+a^2 D\right )}{b^3}\right )\right ) \operatorname {Subst}\left (\int \frac {1}{a-\frac {b c}{d}+\frac {b x^2}{d}} \, dx,x,\sqrt {c+d x}\right )}{d}\\ &=\frac {2 \left (a^2 d^2 D-a b d (C d-c D)-b^2 \left (c C d-B d^2-c^2 D\right )\right ) \sqrt {c+d x}}{b^3 d^3}+\frac {2 (b C d-2 b c D-a d D) (c+d x)^{3/2}}{3 b^2 d^3}+\frac {2 D (c+d x)^{5/2}}{5 b d^3}-\frac {2 \left (A b^3-a \left (b^2 B-a b C+a^2 D\right )\right ) \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}\right )}{b^{7/2} \sqrt {b c-a d}}\\ \end {align*}
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Mathematica [A] time = 0.27, size = 185, normalized size = 0.98 \[ -\frac {2 \left (A b^3-a \left (a^2 D-a b C+b^2 B\right )\right ) \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}\right )}{b^{7/2} \sqrt {b c-a d}}+\frac {2 \sqrt {c+d x} \left (a^2 d^2 D+a b d (c D-C d)+b^2 \left (B d^2+c^2 D-c C d\right )\right )}{b^3 d^3}+\frac {2 (c+d x)^{3/2} (-a d D-2 b c D+b C d)}{3 b^2 d^3}+\frac {2 D (c+d x)^{5/2}}{5 b d^3} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.73, size = 565, normalized size = 3.01 \[ \left [\frac {15 \, {\left (D a^{3} - C a^{2} b + B a b^{2} - A b^{3}\right )} \sqrt {b^{2} c - a b d} d^{3} \log \left (\frac {b d x + 2 \, b c - a d + 2 \, \sqrt {b^{2} c - a b d} \sqrt {d x + c}}{b x + a}\right ) + 2 \, {\left (8 \, D b^{4} c^{3} - 15 \, {\left (D a^{3} b - C a^{2} b^{2} + B a b^{3}\right )} d^{3} + 5 \, {\left (D a^{2} b^{2} c - {\left (C a b^{3} - 3 \, B b^{4}\right )} c\right )} d^{2} + 3 \, {\left (D b^{4} c d^{2} - D a b^{3} d^{3}\right )} x^{2} + 2 \, {\left (D a b^{3} c^{2} - 5 \, C b^{4} c^{2}\right )} d - {\left (4 \, D b^{4} c^{2} d - 5 \, {\left (D a^{2} b^{2} - C a b^{3}\right )} d^{3} + {\left (D a b^{3} c - 5 \, C b^{4} c\right )} d^{2}\right )} x\right )} \sqrt {d x + c}}{15 \, {\left (b^{5} c d^{3} - a b^{4} d^{4}\right )}}, -\frac {2 \, {\left (15 \, {\left (D a^{3} - C a^{2} b + B a b^{2} - A b^{3}\right )} \sqrt {-b^{2} c + a b d} d^{3} \arctan \left (\frac {\sqrt {-b^{2} c + a b d} \sqrt {d x + c}}{b d x + b c}\right ) - {\left (8 \, D b^{4} c^{3} - 15 \, {\left (D a^{3} b - C a^{2} b^{2} + B a b^{3}\right )} d^{3} + 5 \, {\left (D a^{2} b^{2} c - {\left (C a b^{3} - 3 \, B b^{4}\right )} c\right )} d^{2} + 3 \, {\left (D b^{4} c d^{2} - D a b^{3} d^{3}\right )} x^{2} + 2 \, {\left (D a b^{3} c^{2} - 5 \, C b^{4} c^{2}\right )} d - {\left (4 \, D b^{4} c^{2} d - 5 \, {\left (D a^{2} b^{2} - C a b^{3}\right )} d^{3} + {\left (D a b^{3} c - 5 \, C b^{4} c\right )} d^{2}\right )} x\right )} \sqrt {d x + c}\right )}}{15 \, {\left (b^{5} c d^{3} - a b^{4} d^{4}\right )}}\right ] \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 1.26, size = 248, normalized size = 1.32 \[ -\frac {2 \, {\left (D a^{3} - C a^{2} b + B a b^{2} - A b^{3}\right )} \arctan \left (\frac {\sqrt {d x + c} b}{\sqrt {-b^{2} c + a b d}}\right )}{\sqrt {-b^{2} c + a b d} b^{3}} + \frac {2 \, {\left (3 \, {\left (d x + c\right )}^{\frac {5}{2}} D b^{4} d^{12} - 10 \, {\left (d x + c\right )}^{\frac {3}{2}} D b^{4} c d^{12} + 15 \, \sqrt {d x + c} D b^{4} c^{2} d^{12} - 5 \, {\left (d x + c\right )}^{\frac {3}{2}} D a b^{3} d^{13} + 5 \, {\left (d x + c\right )}^{\frac {3}{2}} C b^{4} d^{13} + 15 \, \sqrt {d x + c} D a b^{3} c d^{13} - 15 \, \sqrt {d x + c} C b^{4} c d^{13} + 15 \, \sqrt {d x + c} D a^{2} b^{2} d^{14} - 15 \, \sqrt {d x + c} C a b^{3} d^{14} + 15 \, \sqrt {d x + c} B b^{4} d^{14}\right )}}{15 \, b^{5} d^{15}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.02, size = 338, normalized size = 1.80 \[ \frac {2 A \arctan \left (\frac {\sqrt {d x +c}\, b}{\sqrt {\left (a d -b c \right ) b}}\right )}{\sqrt {\left (a d -b c \right ) b}}-\frac {2 B a \arctan \left (\frac {\sqrt {d x +c}\, b}{\sqrt {\left (a d -b c \right ) b}}\right )}{\sqrt {\left (a d -b c \right ) b}\, b}+\frac {2 C \,a^{2} \arctan \left (\frac {\sqrt {d x +c}\, b}{\sqrt {\left (a d -b c \right ) b}}\right )}{\sqrt {\left (a d -b c \right ) b}\, b^{2}}-\frac {2 D a^{3} \arctan \left (\frac {\sqrt {d x +c}\, b}{\sqrt {\left (a d -b c \right ) b}}\right )}{\sqrt {\left (a d -b c \right ) b}\, b^{3}}+\frac {2 \sqrt {d x +c}\, B}{b d}-\frac {2 \sqrt {d x +c}\, C a}{b^{2} d}-\frac {2 \sqrt {d x +c}\, C c}{b \,d^{2}}+\frac {2 \sqrt {d x +c}\, D a^{2}}{b^{3} d}+\frac {2 \sqrt {d x +c}\, D a c}{b^{2} d^{2}}+\frac {2 \sqrt {d x +c}\, D c^{2}}{b \,d^{3}}+\frac {2 \left (d x +c \right )^{\frac {3}{2}} C}{3 b \,d^{2}}-\frac {2 \left (d x +c \right )^{\frac {3}{2}} D a}{3 b^{2} d^{2}}-\frac {4 \left (d x +c \right )^{\frac {3}{2}} D c}{3 b \,d^{3}}+\frac {2 \left (d x +c \right )^{\frac {5}{2}} D}{5 b \,d^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {A+B\,x+C\,x^2+x^3\,D}{\left (a+b\,x\right )\,\sqrt {c+d\,x}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 66.26, size = 192, normalized size = 1.02 \[ \frac {2 D \left (c + d x\right )^{\frac {5}{2}}}{5 b d^{3}} - \frac {2 \left (c + d x\right )^{\frac {3}{2}} \left (- C b d + D a d + 2 D b c\right )}{3 b^{2} d^{3}} + \frac {2 \left (- A b^{3} + B a b^{2} - C a^{2} b + D a^{3}\right ) \operatorname {atan}{\left (\frac {1}{\sqrt {\frac {b}{a d - b c}} \sqrt {c + d x}} \right )}}{b^{3} \sqrt {\frac {b}{a d - b c}} \left (a d - b c\right )} + \frac {2 \sqrt {c + d x} \left (B b^{2} d^{2} - C a b d^{2} - C b^{2} c d + D a^{2} d^{2} + D a b c d + D b^{2} c^{2}\right )}{b^{3} d^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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